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MTH 607 Graph Theory Lab 8

We will work on these questions in the lab.

  1. Find the line graphs of the graphs below.
    Graph
    Line Graph
    KiteBowtie Dumbell

    1. Find the line graph of the hypercube Q3.

    2. Show that if a simple graph is r regular then its line graph is 2(r-1) regular.

      Consider an edge e = xy of an r regular graph G.
      The edge is incident on r - 1 edges at x and r - 1 edges at y.
      This gives 2(r-1) edges incident with e in G.

    1. Show that given a cycle v0 v1, ..., vk in the line graph of G, the corresponding edges in G also form a cycle.

      Given an edge of G (vertex of L(G)), vi, then vi is adjacent to vi-1 and vi+1 in G. (arithmetic modulo k)
      If two edges in G are incident in G, this would close the cycle in L(G).
      Thus going around the cycle in L(G) gives a cycle in G.

    2. Use the result of a above to show that the line graph of a tree is a tree.

  2. (Ex 5.33) Let G be a 5-connected graph, show that between any 3 distinct vertices u, v and w there are 2 cycles which have C and C' which have only the points u and v in common and do not go through w.

    Let u, v and w be distinct vertices of a 5-connected graph, G.
    Since G is 5-connected, there are at least 5 internally disjoint uv-paths.
    At most one of these paths go through w.
    The remaining 4 paths form 2 cycles which have only the points u and v in common and do not go through w.

  3. Given a graph G and a pair of points u, vV(G), a uv-necklace is a sequence of cycles C1, C2, . . . , Ck such that
    1. u is in C1 and v is in Ck;
    2. Ci, Ci+1 meet in exactly 1 point;
    3. Ci, Cj have no points in common when |i - j| ≠ 0, 1.

    Show that a graph is 2-edge connected if and only if there is a uv-necklace for every pair of vertices u and v.

    (⇒) Let G be a 2-edge connected graph and let u and v be any pair of vertices in V(G).
    Now by Menger's Theorem (edge version) there are at least two edge disjoint uv-paths, P and Q.
    Each time P and Q share a point they create a cycle. Sharing many points creates a necklace.

    (⇐) Let G be a graph for which every pair of vertices u and v is joined by a uv-necklace.
    This means that every pair of points is joined by 2 edge disjoint paths and so G is 2-edge connected by Mengers Theorem (edge version).


Peter Danziger, March 2008